Integrand size = 12, antiderivative size = 37 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{x^{5/2}} \, dx=-\frac {1}{3 x}-\frac {2 \arctan \left (\sqrt {x}\right )}{3 x^{3/2}}-\frac {\log (x)}{3}+\frac {1}{3} \log (1+x) \]
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Time = 0.01 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {4946, 46} \[ \int \frac {\arctan \left (\sqrt {x}\right )}{x^{5/2}} \, dx=-\frac {2 \arctan \left (\sqrt {x}\right )}{3 x^{3/2}}-\frac {1}{3 x}-\frac {\log (x)}{3}+\frac {1}{3} \log (x+1) \]
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Rule 46
Rule 4946
Rubi steps \begin{align*} \text {integral}& = -\frac {2 \arctan \left (\sqrt {x}\right )}{3 x^{3/2}}+\frac {1}{3} \int \frac {1}{x^2 (1+x)} \, dx \\ & = -\frac {2 \arctan \left (\sqrt {x}\right )}{3 x^{3/2}}+\frac {1}{3} \int \left (\frac {1}{x^2}-\frac {1}{x}+\frac {1}{1+x}\right ) \, dx \\ & = -\frac {1}{3 x}-\frac {2 \arctan \left (\sqrt {x}\right )}{3 x^{3/2}}-\frac {\log (x)}{3}+\frac {1}{3} \log (1+x) \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.84 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{x^{5/2}} \, dx=\frac {1}{3} \left (-\frac {1}{x}-\frac {2 \arctan \left (\sqrt {x}\right )}{x^{3/2}}-\log (x)+\log (1+x)\right ) \]
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Time = 0.31 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.70
method | result | size |
derivativedivides | \(-\frac {1}{3 x}-\frac {2 \arctan \left (\sqrt {x}\right )}{3 x^{\frac {3}{2}}}-\frac {\ln \left (x \right )}{3}+\frac {\ln \left (x +1\right )}{3}\) | \(26\) |
default | \(-\frac {1}{3 x}-\frac {2 \arctan \left (\sqrt {x}\right )}{3 x^{\frac {3}{2}}}-\frac {\ln \left (x \right )}{3}+\frac {\ln \left (x +1\right )}{3}\) | \(26\) |
meijerg | \(-\frac {1}{x}+\frac {2}{9}-\frac {\ln \left (x \right )}{3}+\frac {-10 x +30}{45 x}-\frac {2 \arctan \left (\sqrt {x}\right )}{3 x^{\frac {3}{2}}}+\frac {\ln \left (x +1\right )}{3}\) | \(37\) |
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Time = 0.26 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.89 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{x^{5/2}} \, dx=\frac {x^{2} \log \left (x + 1\right ) - x^{2} \log \left (x\right ) - 2 \, \sqrt {x} \arctan \left (\sqrt {x}\right ) - x}{3 \, x^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 143 vs. \(2 (31) = 62\).
Time = 1.36 (sec) , antiderivative size = 143, normalized size of antiderivative = 3.86 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{x^{5/2}} \, dx=- \frac {2 x^{\frac {3}{2}} \operatorname {atan}{\left (\sqrt {x} \right )}}{3 x^{3} + 3 x^{2}} - \frac {2 \sqrt {x} \operatorname {atan}{\left (\sqrt {x} \right )}}{3 x^{3} + 3 x^{2}} - \frac {x^{3} \log {\left (x \right )}}{3 x^{3} + 3 x^{2}} + \frac {x^{3} \log {\left (x + 1 \right )}}{3 x^{3} + 3 x^{2}} - \frac {x^{2} \log {\left (x \right )}}{3 x^{3} + 3 x^{2}} + \frac {x^{2} \log {\left (x + 1 \right )}}{3 x^{3} + 3 x^{2}} - \frac {x^{2}}{3 x^{3} + 3 x^{2}} - \frac {x}{3 x^{3} + 3 x^{2}} \]
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Time = 0.19 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.68 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{x^{5/2}} \, dx=-\frac {2 \, \arctan \left (\sqrt {x}\right )}{3 \, x^{\frac {3}{2}}} - \frac {1}{3 \, x} + \frac {1}{3} \, \log \left (x + 1\right ) - \frac {1}{3} \, \log \left (x\right ) \]
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Time = 0.27 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.76 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{x^{5/2}} \, dx=\frac {x - 1}{3 \, x} - \frac {2 \, \arctan \left (\sqrt {x}\right )}{3 \, x^{\frac {3}{2}}} + \frac {1}{3} \, \log \left (x + 1\right ) - \frac {1}{3} \, \log \left (x\right ) \]
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Time = 0.39 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.73 \[ \int \frac {\arctan \left (\sqrt {x}\right )}{x^{5/2}} \, dx=\frac {\ln \left (x+1\right )}{3}-\frac {2\,\ln \left (\sqrt {x}\right )}{3}-\frac {2\,\mathrm {atan}\left (\sqrt {x}\right )}{3\,x^{3/2}}-\frac {1}{3\,x} \]
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